1. x² – 4x + 2 = 0

a = 1
b = -4
c = 2

D = b² – 4ac = (-4)² – 8 = 16 – 4 = 8

x = ^{-b + √D}/_2ac
^{-b + √8}/_2ac = ^{4 + √8}/₄ = ^{4 + 2√2}/₄ = 1 + 0,5√2
^{-b – √8}/_2ac = ^{4 – √8}/₄ = ^{4 – 2√2}/₄ = 1 – 0,5√2
Պատ․ x = 1 + 0,5√2

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2. /4x – 6 > 7
\8 – 5x > 4 – 3x

+6 |/4x > 13
+3x |\8 – 2x > 4

/4 |/x > 3,25
-8 |\-2x > -4

/-2 |x < 2

/x > 3,25
\x < 2

Պատ․ x ∈ ∅